If **the** **force** F is applied to the handle, **determine** **the** **component** **of** **the** **moment** created about the **z** axis of the valve. 4-56. **Determine** **the** **moment** produced by **force** F about segment AB of the pipe assembly. Express the result as a Cartesian vector. 4-51. **Determine** **the** **moment** produced by **force** F about the diagonal AF of the rectangular block. Two couples act on the beam as shown.If F= 150 lb,determine the resultant couple **moment**. SOLUTION 150 lb couple is resolved into their horizontal and vertical **components** as shown in Fig.a a = 240 lb# ftdAns. + (M R) c= 150 a 4 5 b(1.5) + 150 a 3 5 b(4) - 200(1.5) 200 lb 200 lb 1.5 ft -F 4 3 5 F4 3 5 4 ft 307.

From **point** a on level ground, the angles of elevation of the top t and bottom **b** of a tower situated on the top of a hill are measured as 47º 52’ and 3 9º 36’. find the height of the hill if the.

First, let's figure out the x-component of **force** F_1 F 1. Looking at the diagram, we can see that there is a 60 o angle between the positive x-axis and **force** F_1 F 1. Therefore, the x-component of **force** F_1 F 1 is: F_ {1x}\,=\,5\text {cos}\, (60^0)\,=\,2.5 F 1x = 5cos(600) = 2.5 kN Now, let's figure out the y-component of **force** F_1 F 1. Then the inertia axes **determine the x**, **y and z**-axis of the **component** coordinate system based on the size of their **moments** of inertia. After you determined the axes, the ACIS body reference is represented as a symbol at the center of mass of the ACIS **component** and the dialog for processing the ProStructures **component** characteristics is opened. A magnetic field is directed along **z**, with a magnitude that varies with **x** according to B=B_0(1−xb). If the current in the loop circulates counterclockwise (that is, the magnetic dipole **moment** **of** **the** loop is along the **z** axis), find an expression for the **x**, **y**, **and** **z** projections of the net **force** on the loop.

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Oニニー Wuた a)The light Boonr AB 15 attached to a vertiocal unll at A and supported bytwoables at **B**.A **Force** pisappl... **Determine** the magnitude **of the moment** of P about **the x**-axis in Nm. 2. **Determine** the magnitude of P about the **y**-axis and ... **determine** the magnitude **of the moment** P in **the x**-axis, **y**-axis, **z**-axis, and about the origin O in. The Attempt at a Solution. **Y Component**: 65m*cos (35) = 53.24m. **Z Component**: 65m*cos (55) = 37.28m. I think these two are right, but I don't have a clue how to solve for the.

**Determine** **the** horizontal and vertical **components** **of** all the individual **forces** by using the formula; Horizontal **component** -, Fₓ = F cos θ, Vertical **component** -, Fᵧ = F sin θ, Add the individual horizontal and vertical **components** to get the horizontal and vertical **components** **of** **the** resultant **force**.

**The**water imparts a**force****of**4 N in the x-direction and 1 N in the y-direction, and the wind adds a**force****of**5 N in the x-direction and 3 N in the y-direction. The resultant vector is the**x****components**added together (4 + 5 = 9 N) and the**y****components**added together (3 + 1 = 4 N). So you end up with 9 N in the x-direction and 4 N in the y-direction. Step 1: Write the coordinates of**points**O,A and**B**: O ≡ (0, 0, 0) (since**point**O is the origin). Since**point**A is on the**Z**-axis at**Z**=10.5m, its**X**and**Y**coordinates are 0. ∴ A ≡ (0, 0, 1 0. 5 m)**Point B**is in space, which is 4m from the positive**X**-axis, 3m from the negative**Y**-axis, and 1.5m from the positive**Z**-axis. ∴**B**≡ (4 m, − 3 m. Answer (1 of 3): I am giving you an example of how to find the resultant of 2 velocities v1 and v2 by using the**component**method of v1x, v1y, v2x and v2y. I am providing you the output of my Vector Addition computer program. It used the**component**method of vector addition. V1x is the x-component.**Determine**the**x y z components**of internal loading in the rod at**point**E Units from WERKTUIGBO WB1631 at Delft University of Technology.

**Moment** **about** **B** Substitute xF **y**= 180 to the above equation Thus, F = 75 lb downward to the right at θ **x**= 36.87° and x-intercept at (4, 0). answer 16. In Fig. P-231, a **force** P intersects the **X** axis at 4 ft to the right of O. If its **moment** **about** A is 170 ft·lb counterclockwise and its **moment** **about** **B** is 40 ft·lb clockwise, **determine** its **y** intercept.

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**Determine** (a) the **x**, **y**, **and** **zcomponents** **of** **the** **force** exerted by the cable on the anchor **B**, (**b**) **the** angles θ **x**, θ **y,and** θ **z** defining the direction of that **force**. SOLUTION From triangle AOB: 56 ft cos 65 ft 0.86154 30.51 **y** **y** θ θ (a) sin cos20 (3900 lb)sin30.51 cos20 FF **xy**=− °θ F x=−1861 lbW FF yy=+ =cos (3900 lb)(0.86154)θF y=+3360 lbW F.

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4—54.

**Determine**the magnitude of the**moments**of the**force**F about the**x**,**y**, and**Z**axes. Solve the problem (a) using a Cartesian vector approach and (**b**) using a scalar approach. a).thoughtworks interview questions

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Answer to **Determine** the **x**, **y**, **z components** of **force** and **moment** at **point** C in the pipe assembly. Neglect the weight of the pipe. Take F 1 = [350i – 400j] lb and F 2 = [ | SolutionInn.

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**Determine** the **x**, **y**, and **z components** of the **moment** of this **force about point** A. **Determine** the **x, y, **and **z components** of the moment of this **force about point B**. Who are the experts?.

**Determine** **the** **x**, **y**, **and** **z** **components** **of** **the** **moment** **of** **this** **force** **about** **point** O. Question Transcribed Image Text: The **force** F = {500 i - 200 j - 500 k} lb acts at the end of the beam. F 8 ft 1.5 ft 0.25 ft Part A **Determine** **the** **x**, **y**, **and** **z** **components** **of** **the** **moment** **of** **this** **force** **about** **point** O. Expert Solution Want to see the full answer?. . 4—54. **Determine** the magnitude of the **moments** of the **force** F about the **x**, **y**, and **Z** axes. Solve the problem (a) using a Cartesian vector approach and (**b**) using a scalar approach. a).

Now write scalar **moment** equations about what **point**? **Point** A! M **X** = ( MA)X + 40 (6) - 80 (6 ... EXAMPLE II Given:The uniform plate has a weight of 500 lb, supported by three cables a) Use established **x**, **y** **and** **z** axes.. Find: The tension in each of the supporting cables. Plan: **b**) Draw a FBD of the plate. ... Couple **moment** **B**) ForceB) **Force** C. Then the inertia axes **determine the x**, **y and z**-axis of the **component** coordinate system based on the size of their **moments** of inertia. After you determined the axes, the ACIS body reference is represented as a symbol at the center of mass of the ACIS **component** and the dialog for processing the ProStructures **component** characteristics is opened. Part A The man pulls on the rope with a **force** of F = 30 N as shown in (Figure 1). **Determine** the position vector from O to A. Express the 2, **y**, **and z components** of the position vector in meters to three significant figures separated by commas. **Force** F = 430 N acts perpendicular to the inclined plane (Figure 1). **Determine** **the** **moment** produced by F about **point** **B**. Enter the **x**, **y**, **and** **z** **components** **of** **the** **moment** separated by commas. Mechanical Engineering, Engineering. 32 0. **X** Choose your mode of payment. The centroid of the beam section coincides with the centre of the web 34. The second **moments** of area are calculated using the methods described in Section 9.6 and are:.

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The pipe assembly is subjected to the **force** ofF = {600i + 800j - 500k} N. **Determine** the **moment ofthis force about point** A.The pipe assembly is subjected to t. **The** 24-N horizontal **force** acts on the handle of the socket wrench. **Determine** **the** **x**, **y**, **and** **z** **components** **of** **the** **moment** **of** **this** **force** **about** **point** O. Specify the coordinate direction angles alpha, beta, gamma of the **moment** axis. alpha, beta, gamma = 81.8, 75.7, 163 degree, 1 Approved Answer, Dil A answered on January 08, 2021, 5 Ratings, ( 9 Votes).

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Answer to

**Determine**the**x**,**y**,**z components**of**force**and**moment**at**point**C in the pipe assembly. Neglect the weight of the pipe. Take F 1 = [350i – 400j] lb and F 2 = [ | SolutionInn.• The

**moment****of**inertia (MI) of a plane area about an axis normal to the plane is equal to the sum of the**moments****of**inertia about any two mutually perpendicular axes lying in the plane and passing through the given axis. • That means the**Moment****of**Inertia I**z**= I**x**+I**y**.ear piercing stereotypes

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As stated earlier, when a body is in equilibrium, the net

**force****and****the**net**moment**equal zero, i.e., F = 0 and M O = 0 . These two vector equations can be written as six scalar equations of equilibrium (EofE). These are F**X**= F**Y**= F**Z**= 0 M**X**= M**Y**= M**Z**= 0 The**moment**equations can be determined about any**point**.Explanation:-Plane stress condition: Plane stress is defined to be a state of stress in which the stress in the

**z**-direction, (σ**z**) and the shear stresses, σ xz and σ yz, directed perpendicular to**the x**-**y**plane are assumed to be zero.. i.e. σ**x**≠ 0, σ**y**≠ 0, σ**z**= 0.. The plane stress condition is valid for the**components**for which the**z**-dimension is smaller than**the x**and**y**-dimensions.

**Determine** the **x**, **y**, and **z components** of the **moment** of this **force about point** O.Express your answers using three significant figures separated by commas. Chemical Engineering ,. The centroid of the beam section coincides with the centre of the web 34. The second **moments** of area are calculated using the methods described in Section 9.6 and are:.

in this problem, we have been given that there is a full supply at this **point**. And that **force** factor is given us 300 icap -200 Jacob -5 50. Kick up. And we need to **determine** the **X**, **Y** and **z**.